Question 788143
{{{ f(x)=x^2+x-3 }}}
{{{ g(x) = 9x + 9 }}}
{{{ g(-1) = 9*(-1) + 9 }}}
{{{ g(-1) = 0 }}}
{{{ f( g(-1) ) = f(0) }}}
{{{ f(0) = 0^2 + 0 - 3 }}}
{{{ f(0) = -3 }}}
so, from above,
{{{ f( g(-1) ) = -3 }}}