Question 67157
Difference of squares
{{{t^8-1=(t^4+1)(t^4-1)}}}
Still a Difference of squares
{{{(t^4+1)(t^4-1)=(t^4+1)(t^2+1)(t^2-1)}}}
Still a Difference of squares!
{{{(t^4+1)(t^2+1)(t^2-1)=(t^4+1)(t^2+1)(t+1)(t-1)}}}
Final result
{{{t^8-1=(t^4+1)(t^2+1)(t+1)(t-1)}}}