Question 787794
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No.  We aren't going to do your entire homework assignment for you.


But here are some facts that will help you:


<i><b>Standard Form (also called the General Form)</b></i>


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Ax\ +\ By\ =\ C]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ax\ +\ by\ +\ c\ =\ 0]


A and B (or a and b) cannot both be zero.  Most definitions of this form require that A, B, and C (or a, b, and c) be integers, although this would exclude perfectly valid linear equations just because they happened to have one or more irrational coefficients.


<i><b>Slope-Intercept Form</b></i>


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ b]


Where *[tex \Large m] is the slope and *[tex \Large b] is the *[tex \Large y]-coordinate of the *[tex \Large y]-intercept.


<i><b>Point-Slope Form</b></i>


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given/calculated slope.


<i><b>Two Point Form</b></i>


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


<i><b>Slope Formula</b></i>



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ \frac{y_1\ -\ y_2}{x_1\ -\ x_2} ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


<i><b>Slope Relationships between Parallel and Perpendicular Lines</b></i>


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \not =\, 0]


<i><b>Intercepts</b></i>


The *[tex \Large y]-intercept is the point *[tex \Large (0,b)] where *[tex \Large b] is the value of *[tex \Large y] when *[tex \Large x\ =\ 0].  This is the point where the line intersects the *[tex \Large y]-axis.


The *[tex \Large x]-intercept is the point *[tex \Large (a,0)] where *[tex \Large a] is the value of *[tex \Large x] when *[tex \Large y\ =\ 0].  This is the point where the line intersects the *[tex \Large x]-axis.


Let me know if you have a specific question about a specific problem, which I will be delighted to answer IF you show the work you have done so far.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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