Question 787748
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Since the given equation is in slope-intercept form, you can determine the slope of the line whose graph is the solution set of the given equation by inspection of the coefficient on *[tex \Large x].  And, since parallel lines have identical slopes, you now know the slope of the desired line.  Since you are also given a point on the desired line, you can use the point-slope form of an equation representing a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the known slope.


Once you have substituted your particular numbers and have simplified, multiply by the least common multiple of the denominators of all fractional coefficients, add the additive inverse of any variable term that is in the right hand side to both sides of the equation, and finally add the additive inverse of any constant term that is in the left hand side to both sides of the equation.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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