<PRE><B>Question 787736</B>
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The perimeter of a rectangle is given by *[tex \Large P\ =\ 2l\ +\ 2w]


Where *[tex \Large l] is the length and *[tex \Large w] is the width.


But for this problem, you know that the length is 3 inches more than the width, so *[tex \Large l\ =\ w\ +\ 3].  Also, you know that the perimeter is 38 inches.  Make the substitutions:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \ 2(w\ +\ 3)\ +\ 2w\ =\ 38]


Solve for *[tex \Large w].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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