Question 787588
Sue weighs 45 pounds, and her father weighs 170 pounds. If Sue sits on one end of a 20-foot-long seesaw with the fulcrum in the middle, how far from the fulcrum should her father sit to balance the seesaw?
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Sue is 10 ft from the middle.
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Sue's leverage is 45*10 = 400 ft-lbs
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Dad's leverage is 170x where "x" is his distance from the fulcrum.
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Equation:
170x = 400
x = 2.2857 ft from the fulcrum.
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Cheers,
Stan H.