Question 787574
Let {{{ t }}} = time in hours when the vehicles are
{{{ 5 }}} mi apart
Let {{{ d }}} = distance the car travels in {{{ t }}} hrs
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Equation for car:
(1) {{{ d = 55t }}}
Equation for motorcycle:
(2) {{{ d - 5 = 40t }}}
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Substitute (1) into (2)
(2) {{{ 55t - 5 = 40t }}}
(2) {{{ 15t = 5 }}}
(2) {{{ t = 1/3 }}}
{{{ (1/3)*60 = 20 }}}
They will be 5 mi apart in 20 minutes
check:
(1) {{{ d = 55*(1/3) }}}
(1) {{{ d = 55/3 }}}
and
(2) {{{ d - 5 = 40*(1/3) }}}
(2) {{{ d = 15/3 + 40/3 }}}
(2) {{{ d = 55/3 }}}
OK