<PRE><B>Question 787320</B>
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One more time...from the very top.


Let *[tex \Large x] be &lt;b&gt;&lt;i&gt;the measure of a side&lt;/i&gt;&lt;/b&gt; of one of the cut out squares.


Then the length of the bottom will be *[tex \Large 16\ -\ 2x] because there is a square cut out on each end.  Likewise the width of the bottom after the folding is done will be  *[tex \Large 12\ -\ 2x]


So if you want the length of the bottom to be three times the width:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 16\ -\ 2x\ =\ 3(12\ -\ 2x)]


Solve for *[tex \Large x] which is the side dimension of the squares and sufficient to uniquely identify the size of the squares. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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