Question 787110
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Your explanation falls apart when you said "(pretty much the diameter of the circle)".  It either is or is not the diameter.  If both A and B are on the circle and AB passes through O, then it is a diameter.  If B is somewhere other than on the circle, then it is not a diameter.  You will then need to specify just where point B lies.  Then you said "...segment AC that bisects triangle APB, ..." which doesn't make any sense either because you cannot "bisect" a triangle.  You can bisect any of the angles of a triangle, and I suspect you mean that AC bisects angle A -- presuming you are using the term "bisect" correctly.  Send me an e-mail with a scan of your diagram.


I'll give you one hint to start:  Since AB passes through O, AO must be a radius.  Since AO is a radius it is guaranteed to be perpendicular to a tangent, namely AP, at A.  Hence angle PAB is indeed a right angle.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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