Question 787119

{{{(x-3)/(x+5)<=0}}}

{{{(x-3)<=0(x+5)}}}

{{{x-3<=0}}}

{{{x<=3}}}

since given denominator {{{x+5}}} we need to find {{{x}}} that makes denominator equal to zero and exclude that value from solution because denominator could not be equal to zero

{{{x+5=0}}}   => {{{x=-5}}}

so, the solution set in interval notation: 

{{{-5<x<=3}}} or

({{{-5}}},{{{3}}}]