Question 67230
The cook had x poinds of food in the store house, and this would feed y workers for d days.  Then 50 more workers arrived in camp.  How many days would the cook's food last since (y+50) workers must now be fed?

THE ORIGINAL SOLUTION WAS NOT CORRECT----I'VE TRIED TO MAKE THE CORRECTIONS IN CAPS------ALSO, SEE PROBLEM 67684

LET Z=NUMBER OF DAYS THE FOOD WILL LAST WHEN (Y+50) WORKERS ARE BEING FED


Well, we know that x/y pounds will feed one worker for d days

And we also know that x/(yd) will feed one worker for one day

But we now have (y+50) workers

(x/(yd))(y+50) WILL FEED (Y+50) WORKERS FOR ONE DAY

So,IN Z DAYS, when (x/(yd))(y+50)(Z) equals x, then all the food is gone. So here's our equation to solve and we solve for d (NOT D BUT Z):

(x/(yd))(y+50)(Z)=x  multiply both sides by yd

x(y+50)(Z)=xyd  divide both sides by xy (NOT XY BUT X(Y+50)

Z=XYD/X(Y+50)

Z=YD/(Y+50)----------------CORRECT ANSWER

(x(y+50))/xy=xyd/xy  simplify(NO!!!!!!!!!!)
(y+50)/y=d or (NO!!!!!!!!!!!!!)

d=(y+50)/y  Let's check our dimensions(NO!!!!!!!!!!)

days=(workers-DAYS)/(workers=days  


Hope this helps-----ptaylor