Question 787038
2y^2-5y-3=0

Factor by grouping.

2y^2-6y+y-3 = 0

Factor 2y^2-6y to be 2y(y-3)

We now have 2y(y-3)(y-3).

We only need one (y-3).

The other factor is 2y+1.

Answer: (2y+1)(y-3)