Question 786793

The length {{{L}}} of a rectangle is {{{4}}} times the width {{{W}}}:

{{{L=4W}}}

The perimeter {{{P=35m}}} 

Find the width.

{{{P=2(L+W)}}} ....substitute {{{P=35m}}}  and {{{L=4W}}}

{{{35m=2(4W+W)}}} ......solve for {{{W}}}

{{{35m/2=5W}}}

{{{17.5m=5W}}}

{{{17.5m/5=W}}}

{{{W=3.5m/5}}}

now we can find {{{L}}}

{{{L=4W}}}

{{{L=4*3.5m}}}

{{{L=14m}}}

check the perimeter

{{{P=2(L+W)}}}

{{{P=2(14m+3.5m)}}}

{{{P=2(17.5m)}}}

{{{P=35m}}} which confirms our solution