Question 786585
The trick is to say {{{ x = ln( e^x ) }}} , then
{{{ y = ln( e^x ) - ln(x) }}}
{{{ y = ln( e^x / x ) }}}
Then I can say
{{{ e^y = e^x / x }}}
{{{ x = e^x / e^y }}}
{{{ x = e^( x-y) }}}
Do you need to completely isolate {{{ x }}} on one side?
That's a little tougher