Question 786565
The tan is negative in the 2nd and 4th quadrants.
Between {{{ 0 }}} and {{{ 2*pi }}} radians, the solutions
are {{{ x = (2*pi)/3 }}} and {{{ x = ( 5*pi)/3 }}}
At both these angles, {{{ tan(x) = -sqrt(3) / 1 }}}
-----------------------------------------
Now you have to go to {{{ 2*pi + (2*pi)/3 = (8*pi)/3 }}}
and then to {{{ 2*pi + (5*pi)/3  = 11*pi/3 }}}
-------------------------------------
The progression is:
{{{ (2*pi)/3 }}}
{{{ (5*pi)/3 }}}
{{{ (8*pi)/3 }}}
{{{ (11*pi)/3 }}}
-------------
The general formula would be
{{{ x = (( 2 + 3n )*pi) / 3 }}} ( n = 0,1,2... )