Question 786571
Please help me solve this equation:
(8/m-5)-(4/m+5)=(12/m^2-25)

I have this:
8m+4-4m+20/(m-5)(m+5) = 4m+24/m^2-25=12/m^2-25  *** 8m+40

I don't know if that is correct or what I need to do after that.
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(8/m-5)-(4/m+5)=(12/m^2-25)
I think you mean:
8/(m-5)- 4/(m+5)= 12/(m^2-25)
m^2 - 25 is the common denominator
--> 8(m+5)/DEN - 4(m-5)/DEN = 12/DEN
8m+40 - 4m+20 = 12
4m + 60 = 12
4m = -48
m = -12