Question 786098
{{{((4+3i))/((4-3i))}}}
Multiply by the conjugate of the denominator over itself, (same as multiplying by 1)
{{{((4+3i))/((4-3i))}}} * {{{((4+3i))/((4+3i))}}} 
FOIL
{{{((16+12i+12i+9(i^2)))/((16+12i-12i-9(i^2)))}}} = {{{((16+24i+9(-1)))/((16-9(-1)))}}} = {{{((16+24i-9))/((16+9))}}} = {{{((7+24i))/25}}}