Question 67212
help me solve quadractic equations by graphing:  
y = 2x^2 + 4x - 6
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You could plot some points to see the graph.
or
You could find the vertex at (-b/2a, f(-b/2a))
-b/2a=-4/4=-1 
f(-1)=2-4-6=-8

So the vertex is at (-1,-8)
The y-intercept is at f(0)=-6
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The graph looks like this:
{{{graph(300,200,-10,10,-10,10,2x^2+4x-6)}}}
Cheers,
Stan H.