Question 785504
If the perimeter of the original square park was 220 meters, the length od each side was
{{{220m/4=55m}}}
On a length of {{{55m}}} there are {{{55m/("11 m")=5}}} stretches of {{{11m}}} between statues.
That means that there would be one statue on each corner and 4 statues between the corners on each side.
Since each corners is part of two sides, there are still 25 statues, 5 per side.
I would assign 4 workers to put up the statues, each one putting up 5 statues, starting on a corner, and working clockwise around the park.
{{{drawing(200,200,-1,11,-1,11,
rectangle(0,0,10,10),
red(circle(0,0,0.5)),red(circle(2,0,0.5)),red(circle(4,0,0.5)),red(circle(6,0,0.5)),red(circle(8,0,0.5)),
blue(circle(10,0,0.5)),blue(circle(10,2,0.5)),blue(circle(10,4,0.5)),blue(circle(10,6,0.5)),blue(circle(10,8,0.5)),
circle(10,10,0.5),circle(8,10,0.5),circle(4,10,0.5),circle(6,10,0.5),circle(2,10,0.5),
green(circle(0,10,0.5)),green(circle(0,8,0.5)),green(circle(0,6,0.5)),green(circle(0,4,0.5)),green(circle(0,2,0.5))
)}}}
 
If the other park is 4 times bigger in surface area, that means that each side is twice as large, 110 meters.
That would mean twice as many statues per side, 10 statues per side, and twice as many statues overall, 50 statues in all and 25 more than needed for the smaller park.
 
I thought that I would draw the bigger park, but I changed my mind; that's too many circles.