<PRE><B>Question 785824</B>
A man walks from one town to another in 5 1/2 hrs. Had he
walked 1/4 of a km faster, he would have reached his destination
36 2/3 minutes earlier. Find the distance b/w the two towns and the
rate at which he walked.

let his rate be x km/h

5.5-0.61 =4.89 hours ( time taken after increasing sped)

distance is same
d=rt

5.5x = (x+1/4)*4.89

5.5x=4.89x+1.22

5.5x-4.89x=1.22

0.61x=1.22

x=2 mph

distance = 11 km</PRE>