Question 67199
This problem is simple once you utilize a common law of logarithms.

ln ab = ln a + ln b

On the right hand side of this equation we have ln x + ln 8.  By using the above law, we can write this as ln 8x.

So, we have:
ln({{{x^2}}} + 12) = ln 8x.  So now we know that {{{x^2}}} + 12 = 8x

{{{x^2}}} + 12 = 8x
{{{x^2}}} + 12 - 8x = 0
{{{x^2}}} - 8x + 12 = 0.  We can solve this by using the quadratic formula, but an easier way would be to factor this out as follows:

{{{x^2}}} - 8x + 12 = (x-6) * (x-2).  So, we have:

(x-6)(x-2) = 0.  We know that 0 * anything = 0, so now we can easily see that 
x = 6 or x = 2.  

Hope this helps!!