Question 67161
what is (are) the solution(s) of the equation log sub 4 4x+2 log sub4(x+3)=2
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=log4 [(4x+2)(x+3)] = 2
[(4x+2)(x+3)] =4^2
4x^2+14x+6-16=0
2x^2+7x-5=0
Use the quadratic formula to solve for "x":
x=[-7+-sqrt(49-4*2*-5)]/4
x=[-7+-sqrt89)]/4
x=[-7+9.434]/4
x=0.6085
Cheers,
Stan H.