Question 785546
7x+1)^2+(15x+2)^2=(17x+1)^2

My answer: (7x)^2+2*7x*1+1^2+(15x)^2+2*15x*2+2^2=(17x)^2+2*17x*1+1^2
            
            49x^2+14x+1+225x^2+60x+4=289x^2+34x+1=

             274x^2+74x+5=289x^2+34x+1
             
             74x+5=15x^2+34x+1
      
              40x+5=15x^2+1

               40x=15x^2-4
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{{{15x^2 - 40x - 4 = 0}}}
*[invoke solve_quadratic_equation 15,-40,-4]
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{{{x = 4/3 + 2sqrt(115)/15}}}
{{{x = 4/3 - 2sqrt(115)/15}}}



                 x=15x^2-4/40