Question 785476
{{{3x - 2 ( x + 3 ) = 0}}}
Firstly, expand the {{{2(x+3)}}} using the distributive law, this makes our equation {{{ 3x - 2x + 6 = 0 }}}
Since you didn't provide a method, I will do it the easiest way, the quadratic formula.
{{{ 3x - 2x = 1x = x}}} 
{{{ x + 6 = 0}}}
From here you can say that x = -6 straight away, but using the QUADRATIC FORMULA:
The standard formula that applies to the quadratic formula is {{{ax^2 + bx + c = 0 }}}
a = Coefficient of {{{x^2}}} b = Coefficient of {{{x}}} c = the single number value

a = 0   ({{{1x^2 = 0}}})         b = 1 ({{{x = 1x}}})      c = 6
Quadratic Formula =  {{{x = (-b +- sqrt( b^2-(4*a*c) ))/(2*a) }}}

WE CANNOT DO THIS! AS 2*a = 0 , which means we CANNOT divide by zero.
I will assume that your equation is {{{(3x - 2) ( x + 3 )}}}
Which is expanded to {{{3x^2 + 7x - 6 = 0}}} which is fine for a quadratic equation.

a = 3       b = 7    c = -6
Now we substitute the a, b, and c values that are in your equation into this quadratic formula so it can return 2, (maybe 1 in this case) values of x.

{{{x = (-7 +- sqrt( 7^2-(4*3*-6)))/(2*3) }}}
{{{x = (-7 +- sqrt(49 - -72)) / 6}}}
{{{x = (-7 +- sqrt(49 + 72)) / 6}}}
{{{x = (-7 +- sqrt(121)) / 6}}}
{{{x= (-7 +- 11) / 6}}}
THEREFORE 
{{{x = (-7 + 11) / 6}}}
{{{x  = 4/ 6}}}
{{{x = 0.67}}
or 
{{{x = (-7 - 11) / 6}}}
{{{x = -18/ 6}}}
{{{x = -3}}

{{{x = 0.67 or -3}}}
I personally think you mistyped the equation, it was {{{(3x - 2)( x + 3 ) = 0}}}
not {{{3x - 2 ( x + 3 ) = 0}}}.
Thanks, remember to mark this as your solution if I got it!