Question 785382
7y=5x+6
y=5/7x+6/7
the slop line which is perpendicular to given line is -7/5
the eqation of the line which is passing throw(8,-4)and having slope -7 is
   y-(-4)=-7/5(x-8)
  5(y+4)=-7x+56     
  7x+5y-52=0