Question 785268
1. presently, the ages of a father and his son are 10x and x years respectively.
 In 32 years time, the ratio of their ages will be 2:1.
 Find the sum of their present ages.
:
We know that is 11x, find x
:
{{{(10x+32)/(x+32)}}} = {{{2/1}}}
cross multiply
10x+32 = 2(x+32)
10x + 32 = 2x + 64
10x - 2x = 64 - 32
8x = 32
x = 4
therefore
11(4) = 44 is the sum of their present ages
:
2. In ten years time, a father will be as twice as old as his son.
f + 10 = 2(s+10)
f + 10 = 2s + 20
f = 2s + 20 - 10
f = 2s + 10
 Ten years ago, he was times as old as his son.
Assume the multiplier which is missing, = m
f - 10 = m(s-10)
f - 10 = ms - 10m
Now all you have to do is put in the missing multiplier, and solve it
:
I see one possibility, m=12 then Dad's 34, son's 12
:
 Find the sum of their ages in seven years time. 60?