Question 785157
10 divided by the difference of a number and 2 minus 9 divided by a number plus 2, equals 3 times the recipricol of the difference of the number squared and 4. what is the number?

{{{ (10/(x-2))-(9/(x+2)) = 3*(1/(x^2-4))}}}



Multiply by the LCM {{{x^2-4)}}}

10(x+2)-9(x-2)=3*1
10x+20-9x+18=3

x+38=3

x=-35