Question 784803
An absolute value of some unknown means the unknown can be + or -<P>
Simplify with both the + value of the denominator and the negative value of the denominator.<P>

{{{(x^2+5x+6)/abs(x+2) = (x+2)(x+3)/abs(x+2)}}} = {{{(x+2)(x+3)/ (x+2) = x+3}}} and {{{(x+2)(x+3)/(-(x+2)) = -(x+3) = -x-3}}}