Question 784644
{{{y=b^x}}} would have some general ordered pairs of points, (x,y) same as (x,b^x).  If given the specific point, (2, 1/4), then fit this into the equation form as {{{1/4=b^2}}}.  What is b?  


{{{1/4=(1/2)^2}}},

{{{b^2=(1/2)^2}}}
The simpler answer is {{{highlight(b=1/2)}}}


To finish, x might be any real number, which is why it seems best to choose the positive form of b.
{{{highlight(y=(1/2)^x)}}}