Question 784617
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The radicand of all even-indexed radicals must be non-negative, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x^2\ -\ 8x\ \geq \ 0]


So *[tex \Large x\ \geq \ 0] AND *[tex \Large x\ \geq \ 8], which means *[tex \Large x\ \geq \ 8], hence *[tex \Large \text{dom}f\ =] [*[tex \Large\ 8,\,\infty])



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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