Question 784499
That is a rather large room.
As a math problem, and as stated, it has an infinite number of solutions.
I am listing two solutions with round numbers and realistic dimensions.
 
1) The room's length and breadth could be
14 meters by 4 meters: {{{(14m)*(4m)=56m^2}}}
Then the perimeter would be 36 meters: {{{14m+4m+14m+4m=36m}}}
A wall area of 72 square meter with a room perimeter of 36 meters means a wall height of 2 meters:
{{{72m^2/"36 m"=2m}}}
That's a long room with a low ceiling. It could be  a basement storage room.
 
2) The room's length and breadth could be
8 meters by 7 meters: {{{(8m)*(7m)=56m^2}}}
Then the perimeter would be 30 meters: {{{8m+7m+8m+7m=30m}}}
A wall area of 72 square meter with a room perimeter of 30 meters means a wall height of 2.4 meters:
{{{72m^2/"30 m"=2.4m}}}
That would make a nice size classroom.