Question 783973
2sec^2x=3tanx+1
solve for interval of 0< x <360
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2sec^2x=3tanx+1
2(tan^2x+1)=3tanx+1
2tan^2x+2=3tanx+1
2tan^2x-3tanx+1=0
(2tanx-1)(tanx-1)=0
2tanx-1=0
tanx=1/2
x&#8776;26.57 and 206.57 deg (in quadrant III)
or 
tanx-1=0
tanx=1
x=45 and 225 deg (in quadrant III)