Question 784342
Find the equation of line going through (3,4) and (1,-1).

This is what I've done so far:

m= -1-4/1-3= -5/2  ************** = -5/-2 = 5/2
Use y = mx + b and either point to find b
4 = (5/2)*3 + b
b = -7/2
--> y = (5/2)x - 7/2
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This would work, but the slope is not right.
y-4= -5/2(x-3)
-2(y-4)=-5(x-3)
-2y+8=-5x+15
   -8     -8
-2y/-2y=-5x/-2+7/-2
y=-5/2x+7/-2 ************* -5/2x could be (-5/2)x or -5/(2x).  Add parentheses.