Question 784147
{{{4x^3-25x =0 = x(4x^2 -25)}}}  That gives one solution: x=0<P>
{{{4x^2 -25 = 0}}} <P>
{{{4x^2 = 25}}}<P>
{{{x^2 = 25/4}}}<P>
{{{x=sqrt(25/4)}}} so x= {{{+5/2}}} and {{{-5/2}}}<P>
0, 5/2 and -5/2 are the real solutions/roots.