<PRE><B>Question 784129</B>
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Let *[tex \Large x] represent the first (smallest) odd integer, *[tex \Large x\ +\ 2] represent the second odd integer, and *[tex \Large x\ +\ 4] represent the third odd integer.


Then


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ 3x\ +\ 2(x\ +\ 2)\ =\ 4(x\ +\ 4)\ -\ 1]


Solve for *[tex \Large x], then calculate *[tex \Large x\ +\ 2] and *[tex \Large x\ +\ 4]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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