Question 784100
3/(x-3) + 3 = 15/(x-3)

trying to get x on one side of the equation...

divide both sides by the reciprocal of 3/x-3  which is x-3/3

x-3/3 / 3/(x-3) + 3 = 15/(x-3)times x-3/3

3 = x15-45/x3-9

3= x5-5

add 5 to both sides

8 = x5

divide both sides by 5

x = 8/5