Question 783447
{{{drawing(500,100,-5,5,-0.7,0.3,
grid(1),locate(-1.3,-0.3,4x-2),
arrow(-1.4,-0.38,-4,-0.38),
arrow(-0.5,-0.38,2,-0.38)
)}}} You could count the distance on the drawing as 6 units.
Otherwise, you calculate the distance as the difference:
{{{2-(-4)=2+4=6}}}
Either way, you end up with
{{{4x-2=6}}} --> {{{4x=6+2}}} --> {{{4x=8}}} --> {{{x=8/4}}} --> {{{highlight(x=2)}}}