Question 783443
There is more than one way to get to the solution.
Here is the way I would chose.
Explanations in parentheses probably not required, depending on the teacher.
Some steps may be skipped, depending on the teacher.
 
WITH LOTS OF STEPS AND EXPLANATIONS:
{{{x/5-2=x/3}}}
{{{15*(x/5-2)=15*(x/3)}}} (multiplying both sides of the equal sign times 15 to eliminate denominators)
{{{15*(x/5)-15*2=15*x/3)}}} (applying distributive property on the left side, simplifying on the right)
{{{15*x/5-30=5x)}}} (simplifying)
{{{3x-30=5x)}}} (simplifying)
{{{3x-30-3x=5x-3x)}}} (subtracting {{{3x}}} from both sides of the equal sign)
{{{-30=2x)}}} (simplyfying/collecting like terms)
{{{-30/2=2x/2)}}} (dividing both sides of the equal sign by 2)
{{{-15=x)}}} (simplifying)
 
STREAMLINED VERSION:
{{{x/5-2=x/3}}}
{{{15*(x/5-2)=15*(x/3)}}}
{{{3x-30=5x)}}}
{{{-30=5x-3x)}}}
{{{-30=2x)}}}
{{{-30/2=x)}}}
{{{-15=x)}}}