Question 783561
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Start with either one of your equations.


<b>Step 1.</b>  Pick a value for <i>x</i>.  It can be anything you like, but 0, 1, or some other small integer usually works well and makes the arithmetic easier.


<b>Step 2.</b>  Substitute that value in place of <i>x</i> in your equation.  Do the arithmetic and determine the value of <i>y</i> that results.


<b>Step 3.</b>  Take the value of <i>x</i> that you selected for step 1 and the value of <i>y</i> that you calculated in step 2 and form an ordered pair (<i>x</i>,<i>y</i>).


<b>Step 4.</b>  Plot the ordered pair from Step 3 on your graph.  Remember that the <i>x</i> value is the distance right or left along the horizontal axis and the <i>y</i> value is the distance up or down along the vertical axis.


<b>Step 5.</b>  Repeat steps 1 through 4 with a different value for <i>x</i>.


<b>Step 6.</b>  Draw a line across your graph that passes through the two points that you plotted.


<b>Step 7.</b>  Repeat steps 1 through 6 using the other equation.


The point where the lines intersect is the solution, because the coordinates of that point will satisfy (read: make true) both of your equations.  You need to determine, by inspection of the graph, what the coordinates of that point are and report your answer as an ordered pair, (<i>x</i>,<i>y</i>), using those coordinates.  To check your answer, you should substitute this set of coordinates into each of your original equations and verify that you have a true statement for each of the equations.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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