Question 66990
log(4^8) + log(4^6) = log(4^(3x+2))
8*log(4) + 6*log(4) = (3x + 2)*log(4)
8 + 6 = 3x + 2
14 = 3x + 2
12 = 3x
4 = x
{{{graph(300,300,-3,5,-10,10,log(10,4^8) + log(10,4^6),log(10,4^(3x+2)))}}}