Question 783400
Let x = amt of 74 degree water to be drain & amt of 140 degree water to be added
Find the no. of gallons total
{{{(80*84*10)/231}}} ~ 290 gallons
:
74(290-x) + 140x = 92(290)
21460 - 74x + 140x = 26680
-74x + 140x = 26680 - 21460
66x = 5220
x = 5220/66
x ~ 79 gallons
:
Drain 79 gallons of the 74 degree water out
Add 79 gallons of the 140 degree water
Should result in 92 degree water