Question 783437
2x^2+2y^2+4y=0 and I am supposed to find the center and the radius of the circle 
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Complete the square on the x-terms and on the y-terms:::
2(x^2) + 2(y^2+2y) = 0
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2(x-0)^2 + 2(y^2+2y+1) = 2
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2(x-0)^2 + 2(y+1)^2 = 2
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(x-0)^2 + (y+1)^2 = 1
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Center: (0,-1)
Radus : sqrt(2)
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Cheers,
Stan H.
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