<PRE><B>Question 783407</B>
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The amount of pure acid in 5 liters of 30% solution is *[tex \Large 0.3(5)] liters.  The amount of pure acid in *[tex \Large x] liters of 10% solution is *[tex \LARGE 0.1x] liters.   Mixed together, the amount of pure acid in *[tex \Large 5\ +\ x] liters of 15% solution is either *[tex \Large 0.3(5)\ +\ 0.1x\ ] or *[tex \Large \ 0.15(5\ +\ x)], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.3(5)\ +\ 0.1x\ =\ 0.15(5\ +\ x)]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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