Question 783369
The 4th term of g.p is 108 and the 6th term is 972 what are the possible two value of the (1)common ratio (2)the 3rd term.
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General Term: a(n) = a(1)*r^(n-1)
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Your Problem::
 a*r^5 = 972
 a*r^3 = 108
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(1)common ratio 
Divide to get: r^2 = 9
So r = 3
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Solve for "a"
a*r^3 = a*3^3 = 108
27a = 108
a = 4
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(2)the 3rd term
a*r^2 = 4*9 = 36
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Cheers,
Stan H.
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