Question 782910
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If she does end up with an average of 80, then you had to have divided some number by 3 to get 80.  Whatever that is must be the sum of the three test scores.  So 3 times X minus the sum of the two scores she has already is the smallest score she can get on the third test and still average X.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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