Question 67019
If {{{f(x) = x^2-7x+10}}} evaluate:
a. {{{f(0)}}}
b. {{{f(5)}}}
c. {{{f(-2)}}} 
All you do is just replace the x in the equation with the given value and work out the result:
a. {{{f(0) = 0^2-7(0)+10}}}
{{{f(0) = 10}}} 

b. {{{f(5) = 5^2-7(5)+10}}}
{{{f(5) = 25-35+10}}}
{{{f(5) = 0}}}

c. {{{f(-2) = (-2)^2-7(-2)+10}}}
{{{f(-2) = 4+14+10}}}
{{{f(-2) = 28}}}