Question 782806
{{{a^12 + a^6 + 1}}}
= {{{(a^2)^6 + a^6 + 1}}}
= {{{(a-1)^6 + a^6 + 1}}}
= {{{((a-1)^2)^3 + a^6 + 1}}}
= {{{(a^2+2a+1)^3 + a^6 + 1}}}
= {{{(a+2a)^3 + a^6 + 1}}}
= {{{(3a)^3 + a^6 + 1}}}
= {{{27a^3 + (a^2)^3 + 1}}}
= {{{27a^3 + (a-1)^3 + 1}}}
= {{{27a^3 + a^3-3a^2+3a-1 + 1}}}
= {{{28a^3 -3a^2+3a}}}
= {{{28a^3 +3(-a^2+a)}}}
= {{{28a^3 +3(1)}}}
= {{{28a^3 +3}}}