Question 782739
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2)  Given *[tex \LARGE \cos\theta\ =\ \frac{24}{25}\ \ ] and *[tex \LARGE \ \ 0\ <\theta<\ \frac{\pi}{2}], find *[tex \LARGE \cos(2\theta)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos(2\varphi)\ =\ 2\cos^2\varphi\ -\ 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos(2\theta)\ =\ 2\left(\frac{24}{25}\right)^2\ -\ 1]


Just do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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