Question 782667
ten years ago a man was as old as his wife is now. The man is now twice as old as his wife was then. How old are they both now?
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now:
let x=age of wife
x+10=age of man
..
10 yrs ago:
x-10=age of wife
x=age of man
..
x+10=2(x-10)
x+10=2x-20
x=30
x+10=40
age of wife now=30
age of man now=40