Question 782304
{{{f(2)=4a+2b+c=7}}}

{{{f(0)=c=-3}}}

{{{f(-1)=a-b+c=-2}}}

Write the system of equations:

{{{ system(4a+2b=10, a-b=1, c=-3)}}} Solving this system we get:a=2, b=1, c=-3

Substituting these values into the initial equation we get:

{{{f(x)=2x^2+x-3}}}.